We read your photo as:

What is the fraction for 6.-40>2

Mathematics

ScanSolve AI Answer

Answer

448

59\dfrac{5}{9}

\16.67$

Step-by-step solution

5 steps
  1. Find the total cost of the items costing $48.12, $48.20, and $48.00.

    Formula: total cost = price1_1 + price2_2 + price3_3

    Substitute: 48.12+48.20+48.0048.12 + 48.20 + 48.00

    Add the dollars first: 48+48+48=14448 + 48 + 48 = 144

    Add the cents: 0.12+0.20+0.00=0.320.12 + 0.20 + 0.00 = 0.32

    Total cost = $144.32

    Total cost: $144.32

  2. How much is 8% tax on the total cost.

    Formula: tax = 0.08×0.08 \times total cost

    Substitute: 0.08×144.320.08 \times 144.32

    First compute 0.01×144.32=1.44320.01 \times 144.32 = 1.4432

    Then 8×1.4432=11.5456≈11.558 \times 1.4432 = 11.5456 \approx 11.55 (rounded to nearest cent)

    Total to pay = 144.32+11.55=155.87144.32 + 11.55 = 155.87

    Tax: 11.55∗∗∗∗Totalpayment:11.55** **Total payment: 155.87

  3. Add 146+302146 + 302 using expanded form (no units specified).

    Write in expanded form:

    146=100+40+6146 = 100 + 40 + 6 302=300+0+2302 = 300 + 0 + 2

    Add hundreds: 100+300=400100 + 300 = 400
    Add tens: 40+0=4040 + 0 = 40
    Add units: 6+2=86 + 2 = 8

    Combine: 400+40+8=448400 + 40 + 8 = 448

    Sum: 448
    448

  4. Simplify 4072\frac{40}{72} to test the statement k=4072=47k = \frac{40}{72} = \frac{4}{7}.

    Formula: divide numerator and denominator by GCD(40,72) = 8

    Substitute: 40÷872÷8=59\frac{40 \div 8}{72 \div 8} = \frac{5}{9}

    Check: 59≈0.556\frac{5}{9} \approx 0.556, 47≈0.571\frac{4}{7} \approx 0.571 (not equal)

    Statement is false.

    \dfrac{5}{9}

  5. Cost for 30 min if $40 for 72 min.

    Rate per min = 4072=59\frac{40}{72} = \frac{5}{9} dollars per min

    Cost for 30 min: 59×30=1509=16.6‾≈16.67\frac{5}{9} \times 30 = \frac{150}{9} = 16.\overline{6} \approx 16.67 dollars

    **Cost: 16.67** \16.67

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question