Two airports A and B are such that B is 500 km due East of A. At the same time, plane P and Q take off from A and B respectively. Plane P flies at 360 km/h on a bearing of 030°. Plane Q flies at 240 k

• Plane P (from A): $$\text{Distance}_P = \text{Speed}_P \times \text{Time}$$ $$\text{Distance}_P = 360 \text{ km/h} \times 1.5 \text{ h} = 540 \text{ km}$$
• Plane Q (from B): $$\text{Distance}_Q = \text{Speed}_Q \times \text{Time}$$ $$\text{Distance}_Q = 240 \text{ km/h} \times 1.5 \text{ h} = 360 \text{ km}$$

The given scale is 1:10,000,000.
This means 1 unit on the drawing represents 10,000,000 units in reality.
Let's convert this to a more practical unit for distance:

So, 1 cm on the drawing represents 100 km in reality.

• Distance between A and B on drawing: $$\text{Length}_{AB} = \frac{500 \text{ km}}{100 \text{ km/cm}} = 5 \text{ cm}$$
• Distance travelled by Plane P on drawing: $$\text{Length}_P = \frac{540 \text{ km}}{100 \text{ km/cm}} = 5.4 \text{ cm}$$
• Distance travelled by Plane Q on drawing: $$\text{Length}_Q = \frac{360 \text{ km}}{100 \text{ km/cm}} = 3.6 \text{ cm}$$

To draw the positions, follow these steps:

1. Establish Airport A: Choose a point on your paper, preferably towards the bottom left, and label it A. This represents Airport A.
2. **