Two similar trapeziums have heights of 10 cm and 16 cm. Find the ratio of their areas.

April 6, 2026Mathematics

ScanSolve AI Answer

April 6, 2026

Answer

\frac{10}{16} = \frac{5}{8}$$

Here are the solutions to your questions:

SECTION A

Find the ratio of their area The heights of two similar trapeziums are $10 \text{ cm}$ and $16 \text{ cm}$ . Step 1: Find the ratio of their corresponding linear dimensions (heights). $\text{Ratio of heights} = \frac{10}{16} = \frac{5}{8}$ Step 2: For similar figures, the ratio of their areas is the square of the ratio of their corresponding linear dimensions.

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SECTION A 8. Find the ratio of their area The heights of two similar trapeziums are 10 cm and 16 cm.

Asked on April 6, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 6, 2026

Here are the solutions to your questions: SECTION A 8. Find the ratio of their area The heights of two similar trapeziums are 10 cm and 16 cm. Step 1: Find the ratio of their corresponding linear dimensions (heights). Ratio of heights = (10)/(16) = (5)/(8) Step 2: For similar figures, the ratio of their areas is the square of the ratio of their corresponding linear dimensions. Ratio of areas = ((5)/(8))^2 = (5^2)/(8^2) = 25