We read your photo as:

Use differentiation to determine the point(s) of inflection of the function: y = x³ + 2x² − 5x − 6

Mathematics

ScanSolve AI Answer

Answer

(−23,−5627)\left(-\frac{2}{3}, -\frac{56}{27}\right)

Graph of y = x³ + 2x² − 5x − 6

Use the left and right arrow keys to trace the curve, up and down to jump between key points, and plus and minus to zoom.

Key points of y = x³ + 2x² − 5x − 6
Pointxy
x-intercept−30
Maximum−2.124.06
x-intercept−10
y-intercept0−6
Minimum0.79−8.21
x-intercept20

Step-by-step solution

5 steps
  1. Find the first derivative of the function.

    The given function is y=x3+2x2−5x−6y = x^3 + 2x^2 - 5x - 6.
    Differentiate yy with respect to xx:

    dydx=ddx(x3)+ddx(2x2)−ddx(5x)−ddx(6)\frac{dy}{dx} = \frac{d}{dx}(x^3) + \frac{d}{dx}(2x^2) - \frac{d}{dx}(5x) - \frac{d}{dx}(6) dydx=3x2+4x−5\frac{dy}{dx} = 3x^2 + 4x - 5
  2. Find the second derivative of the function.

    Differentiate dydx\frac{dy}{dx} with respect to xx:

    d2ydx2=ddx(3x2)+ddx(4x)−ddx(5)\frac{d^2y}{dx^2} = \frac{d}{dx}(3x^2) + \frac{d}{dx}(4x) - \frac{d}{dx}(5) d2ydx2=6x+4\frac{d^2y}{dx^2} = 6x + 4
  3. Set the second derivative to zero to find potential points of inflection.

    Points of inflection occur where the concavity changes, which typically happens when d2ydx2=0\frac{d^2y}{dx^2} = 0.

    6x+4=06x + 4 = 0 6x=−46x = -4 x=−46x = -\frac{4}{6} x=−23x = -\frac{2}{3}
  4. Verify that the concavity changes at x=−23x = -\frac{2}{3}.

    We can check the sign of y′′y'' for values of xx less than and greater than −23-\frac{2}{3}.
    If x<−23x < -\frac{2}{3} (e.g., x=−1x = -1): y′′=6(−1)+4=−6+4=−2<0y'' = 6(-1) + 4 = -6 + 4 = -2 < 0 (concave down).
    If x>−23x > -\frac{2}{3} (e.g., x=0x = 0): y′′=6(0)+4=4>0y'' = 6(0) + 4 = 4 > 0 (concave up).
    Since the sign of y′′y'' changes at x=−23x = -\frac{2}{3}, this is indeed an inflection point.

  5. Substitute the xx-value back into the original function to find the corresponding yy-coordinate.

    Substitute x=−23x = -\frac{2}{3} into y=x3+2x2−5x−6y = x^3 + 2x^2 - 5x - 6:

    y=(−23)3+2(−23)2−5(−23)−6y = \left(-\frac{2}{3}\right)^3 + 2\left(-\frac{2}{3}\right)^2 - 5\left(-\frac{2}{3}\right) - 6 y=−827+2(49)+103−6y = -\frac{8}{27} + 2\left(\frac{4}{9}\right) + \frac{10}{3} - 6 y=−827+89+103−6y = -\frac{8}{27} + \frac{8}{9} + \frac{10}{3} - 6

    To combine these, find a common denominator, which is 27:

    y=−827+8×39×3+10×93×9−6×271×27y = -\frac{8}{27} + \frac{8 \times 3}{9 \times 3} + \frac{10 \times 9}{3 \times 9} - \frac{6 \times 27}{1 \times 27} y=−827+2427+9027−16227y = -\frac{8}{27} + \frac{24}{27} + \frac{90}{27} - \frac{162}{27} y=−8+24+90−16227y = \frac{-8 + 24 + 90 - 162}{27} y=16+90−16227y = \frac{16 + 90 - 162}{27} y=106−16227y = \frac{106 - 162}{27} y=−5627y = -\frac{56}{27}

    The point of inflection is (−23,−5627)\left(-\frac{2}{3}, -\frac{56}{27}\right).

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question