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Use logarithm table to evaluate 53.76 x 0.536 / (0.124)3 x 0.325. (b) Solve the equation 3/(x+2) = 5/(2(x-3)). 12. Table 2.3: Frequency distribution (a) Draw the ogive for Table 2.3. (b) Use the ogive to estimate the: (i) Median (ii) Lower and upper quartiles (iii) Semi-interquartile range

Mathematics

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2 parts
a
46520
b

x=−8x = -8

Step-by-step solution

12 steps

Part a· 6 steps

Use logarithm table to evaluate 53.76×0.536(0.124)3×0.325\frac{53.76 \times 0.536}{(0.124)^3 \times 0.325}.

  1. Let P=53.76×0.536(0.124)3×0.325P = \frac{53.76 \times 0.536}{(0.124)^3 \times 0.325}.

    Take the logarithm of both sides.

    log⁡P=log⁡(53.76×0.536)−log⁡((0.124)3×0.325)\log P = \log(53.76 \times 0.536) - \log((0.124)^3 \times 0.325) log⁡P=(log⁡53.76+log⁡0.536)−(3log⁡0.124+log⁡0.325)\log P = (\log 53.76 + \log 0.536) - (3 \log 0.124 + \log 0.325)
  2. Find the logarithms of each number using a logarithm table.

    • log⁡53.76=1.7305\log 53.76 = 1.7305
    • log⁡0.536=1ˉ.7292\log 0.536 = \bar{1}.7292
    • log⁡0.124=1ˉ.0934\log 0.124 = \bar{1}.0934
    • log⁡0.325=1ˉ.5119\log 0.325 = \bar{1}.5119
  3. Calculate the logarithm of the numerator.

    log⁡(53.76×0.536)=1.7305+1ˉ.7292\log(53.76 \times 0.536) = 1.7305 + \bar{1}.7292 =1.7305+(−1+0.7292)= 1.7305 + (-1 + 0.7292) =0.7305+0.7292=1.4597= 0.7305 + 0.7292 = 1.4597
  4. Calculate the logarithm of the denominator.

    3log⁡0.124=3×(1ˉ.0934)=3×(−1+0.0934)=−3+0.2802=3ˉ.28023 \log 0.124 = 3 \times (\bar{1}.0934) = 3 \times (-1 + 0.0934) = -3 + 0.2802 = \bar{3}.2802 log⁡((0.124)3×0.325)=3ˉ.2802+1ˉ.5119\log((0.124)^3 \times 0.325) = \bar{3}.2802 + \bar{1}.5119 =(−3+0.2802)+(−1+0.5119)= (-3 + 0.2802) + (-1 + 0.5119) =−4+0.7921=4ˉ.7921= -4 + 0.7921 = \bar{4}.7921
  5. Calculate log⁡P\log P.

    log⁡P=1.4597−4ˉ.7921\log P = 1.4597 - \bar{4}.7921 log⁡P=1.4597−(−4+0.7921)\log P = 1.4597 - (-4 + 0.7921) log⁡P=1.4597+4−0.7921\log P = 1.4597 + 4 - 0.7921 log⁡P=5.4597−0.7921\log P = 5.4597 - 0.7921 log⁡P=4.6676\log P = 4.6676
  6. Find the antilog of 4.6676.

    The mantissa is 0.6676. From the antilog table, the antilog of 0.6676 is approximately 4.652.
    The characteristic is 4, so the number has 4+1=54+1=5 digits before the decimal point.

    P=46520P = 46520

    The value is 46520\boxed{46520}.

Part b

x=−8x = -8

Solve the equation 3(x+2)−12(x−3)=5x−3\frac{3}{(x+2)} - \frac{1}{2(x-3)} = \frac{5}{x-3}.

  1. Identify restrictions on xx.

    The denominators cannot be zero, so x≠−2x \neq -2 and x≠3x \neq 3.

  2. Rearrange the equation to group terms with common denominators.

    Move the term 12(x−3)\frac{1}{2(x-3)} to the right side of the equation.

    3(x+2)=5x−3+12(x−3)\frac{3}{(x+2)} = \frac{5}{x-3} + \frac{1}{2(x-3)}
  3. Combine the terms on the right side by finding a common denominator, which is 2(x−3)2(x-3).

    3(x+2)=5×22(x−3)+12(x−3)\frac{3}{(x+2)} = \frac{5 \times 2}{2(x-3)} + \frac{1}{2(x-3)} 3(x+2)=10+12(x−3)\frac{3}{(x+2)} = \frac{10 + 1}{2(x-3)} 3(x+2)=112(x−3)\frac{3}{(x+2)} = \frac{11}{2(x-3)}
  4. Cross-multiply to eliminate the denominators.

    3×2(x−3)=11×(x+2)3 \times 2(x-3) = 11 \times (x+2) 6(x−3)=11(x+2)6(x-3) = 11(x+2)
  5. Distribute and solve for xx.

    6x−18=11x+226x - 18 = 11x + 22

    Subtract 6x6x from both sides and subtract 22 from both sides.

    −18−22=11x−6x-18 - 22 = 11x - 6x −40=5x-40 = 5x

    Divide by 5.

    x=−405x = \frac{-40}{5} x=−8x = -8
  6. Check the solution against the restrictions.

    Since x=−8x=-8 is not equal to −2-2 or 3, the solution is valid.
    The solution is x=−8\boxed{x = -8}.

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