a) Use logarithm table to evaluate (0.124)3×0.32553.76×0.536.
Step 1: Let P=(0.124)3×0.32553.76×0.536. Take the logarithm of both sides.
logP=log(53.76×0.536)−log((0.124)3×0.325)
logP=(log53.76+log0.536)−(3log0.124+log0.325)
Step 2: Find the logarithms of each number using a logarithm table.
• log53.76=1.7305
• log0.536=1ˉ.7292
• log0.124=1ˉ.0934
• log0.325=1ˉ.5119
Step 3: Calculate the logarithm of the numerator.
log(53.76×0.536)=1.7305+1ˉ.7292
=1.7305+(−1+0.7292)
=0.7305+0.7292=1.4597
Step 4: Calculate the logarithm of the denominator.
3log0.124=3×(1ˉ.0934)=3×(−1+0.0934)=−3+0.2802=3ˉ.2802
log((0.124)3×0.325)=3ˉ.2802+1ˉ.5119
=(−3+0.2802)+(−1+0.5119)
=−4+0.7921=4ˉ.7921
Step 5: Calculate logP.
logP=1.4597−4ˉ.7921
logP=1.4597−(−4+0.7921)
logP=1.4597+4−0.7921
logP=5.4597−0.7921
logP=4.6676
Step 6: Find the antilog of 4.6676.
The mantissa is 0.6676. From the antilog table, the antilog of 0.6676 is approximately 4.652.
The characteristic is 4, so the number has 4+1=5 digits before the decimal point.
P=46520
The value is 46520.
b) Solve the equation (x+2)3−2(x−3)1=x−35.
Step 1: Identify restrictions on x. The denominators cannot be zero, so x=−2 and x=3.
Step 2: Rearrange the equation to group terms with common denominators.
Move the term 2(x−3)1 to the right side of the equation.
(x+2)3=x−35+2(x−3)1
Step 3: Combine the terms on the right side by finding a common denominator, which is 2(x−3).
(x+2)3=2(x−3)5×2+2(x−3)1
(x+2)3=2(x−3)10+1
(x+2)3=2(x−3)11
Step 4: Cross-multiply to eliminate the denominators.
3×2(x−3)=11×(x+2)
6(x−3)=11(x+2)
Step 5: Distribute and solve for x.
6x−18=11x+22
Subtract 6x from both sides and subtract 22 from both sides.
−18−22=11x−6x
−40=5x
Divide by 5.
x=5−40
x=−8
Step 6: Check the solution against the restrictions.
Since x=−8 is not equal to −2 or 3, the solution is valid.
The solution is x=−8.
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