Use multiple-base materials to model the given numbers.

$$143000 = 1 \times 100000 + 4 \times 10000 + 3 \times 1000$$

This means:

• 1 hundred thousand block
• 4 ten thousand blocks
• 3 thousand blocks
• 0 hundred flats
• 0 ten rods
• 0 unit cubes The model for 143000 is:

$$\boxed{\text{1 hundred thousand, 4 ten thousands, 3 thousands}}$$

$$327000 = 3 \times 100000 + 2 \times 10000 + 7 \times 1000$$

This means:

• 3 hundred thousand blocks
• 2 ten thousand blocks
• 7 thousand blocks The model for 327000 is:

$$\boxed{\text{3 hundred thousands, 2 ten thousands, 7 thousands}}$$

$$361000 = 3 \times 100000 + 6 \times 10000 + 1 \times 1000$$

This means:

• 3 hundred thousand blocks
• 6 ten thousand blocks
• 1 thousand block The model for 361000 is:

$$\boxed{\text{3 hundred thousands, 6 ten thousands, 1 thousand}}$$

$$112000 = 1 \times 100000 + 1 \times 10000 + 2 \times 1000$$

This means:

• 1 hundred thousand block
• 1 ten thousand block
• 2 thousand blocks The model for 112000 is:

$$\boxed{\text{1 hundred thousand, 1 ten thousand, 2 thousands}}$$

$$237000 = 2 \times 100000 + 3 \times 10000 + 7 \times 1000$$

This means:

• 2 hundred thousand blocks
• 3 ten thousand blocks
• 7 thousand blocks The model for 237000 is:

$$\boxed{\text{2 hundred thousands, 3 ten thousands, 7 thousands}}$$