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Use squares, square roots, and reciprocal tables to evaluate 3.0452 + (1)/(sqrt(49.24)).

Mathematics

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Answer

4
9.4145

Step-by-step solution

6 steps

Part 4· 4 steps

Use squares, square roots, and reciprocal tables to evaluate 3.0452+149.243.045^2 + \frac{1}{\sqrt{49.24}}.

  1. Evaluate 3.04523.045^2.

    Using square tables with interpolation or a calculator for precision:

    3.0452=9.2720253.045^2 = 9.272025

    Rounding to 4 decimal places, as is common with table usage:

    3.0452≈9.27203.045^2 \approx 9.2720
  2. Evaluate 49.24\sqrt{49.24}.

    Using square root tables:
    Look up 49.2\sqrt{49.2}. This value is approximately 7.014.
    The mean difference for the fourth digit '4' is 3.
    So, 49.24=7.014+0.003=7.017\sqrt{49.24} = 7.014 + 0.003 = 7.017.

  3. Evaluate 149.24=17.017\frac{1}{\sqrt{49.24}} = \frac{1}{7.017}.

    Using reciprocal tables:
    Look up the reciprocal of 7.01. This value is approximately 0.14265.
    The mean difference for the fourth digit '7' is 16. For reciprocals, the mean difference is subtracted.
    So, 17.017=0.14265−0.00016=0.14249\frac{1}{7.017} = 0.14265 - 0.00016 = 0.14249.
    Rounding to 4 decimal places:

    149.24≈0.1425\frac{1}{\sqrt{49.24}} \approx 0.1425
  4. Add the two values.

    3.0452+149.24≈9.2720+0.14253.045^2 + \frac{1}{\sqrt{49.24}} \approx 9.2720 + 0.1425 ≈9.4145\approx 9.4145

    The evaluated expression is 9.4145\boxed{9.4145}.

Part 5· 2 steps

Simplify the expression 9x2−25y26x2−19xy+15y2\frac{9x^2 - 25y^2}{6x^2 - 19xy + 15y^2}.

  1. Factor the numerator.

    The numerator is a difference of squares, a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b).
    Here, a=3xa = 3x and b=5yb = 5y.

    9x2−25y2=(3x)2−(5y)2=(3x−5y)(3x+5y)9x^2 - 25y^2 = (3x)^2 - (5y)^2 = (3x - 5y)(3x + 5y)
  2. Factor the denominator.

    The denominator is a quadratic expression 6x2−19xy+15y26x^2 - 19xy + 15y^2. We look for two binomials (ax+by)(cx+dy)(ax+by)(cx+dy).
    By inspection or trial and error, we find the factors:

    6x2−19xy+15y2=(2x−3y)(3x−5y)6x^2 - 19xy + 15y^2 = (2x - 3y)(3x - 5y)

    To verify:
    (2x)(3x)=6x2(2x)(3x) = 6x^2
    (2x)(−5y)=−10xy(2x)(-5y) = -10xy
    $(-3y)(3x) = -9xy

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