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Use the completing the square method to find the exact roots of the equation: 2x2 − 2x + 10 = 0

Mathematics

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Answer

x=6±26x = 6 \pm \sqrt{26}

Step-by-step solution

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Tunatakiwa kutatua mlinganyo wa quadratic x2−12x+10=0x^2 - 12x + 10 = 0 kwa kutumia njia ya kukamilisha mraba.

  1. Hamisha namba isiyo na xx (constant term) upande wa kulia wa mlinganyo.

    x2−12x=−10x^2 - 12x = -10
  2. Ili kukamilisha mraba upande wa kushoto, chukua nusu ya mgawo wa xx (ambayo ni −12-12), kisha ipandishe mraba.

    Mgawo wa xx ni −12-12.
    Nusu ya −12-12 ni −122=−6\frac{-12}{2} = -6.
    Mraba wa −6-6 ni (−6)2=36(-6)^2 = 36.

  3. Ongeza namba hii (36) pande zote mbili za mlinganyo.

    x2−12x+36=−10+36x^2 - 12x + 36 = -10 + 36 x2−12x+36=26x^2 - 12x + 36 = 26
  4. Andika upande wa kushoto kama mraba kamili.

    (x−6)2=26(x - 6)^2 = 26
  5. Chukua mzizi wa mraba pande zote mbili za mlinganyo.

    Kumbuka kuwa kuna majibu mawili, chanya na hasi.

    (x−6)2=±26\sqrt{(x - 6)^2} = \pm\sqrt{26} x−6=±26x - 6 = \pm\sqrt{26}
  6. Tatua kwa xx kwa kuongeza 6 pande zote mbili.

    x=6±26x = 6 \pm\sqrt{26}

    Hivyo, mizizi ya mlinganyo ni:

    x1=6+26x_1 = 6 + \sqrt{26} x2=6−26x_2 = 6 - \sqrt{26}
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