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Use the distributive property of matrix multiplication.

Mathematics

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6. Prove that (A+B)(C+D)=AC+AD+BC+BD(A+B)(C+D) = AC + AD + BC + BD.

  1. Use the distributive property of matrix multiplication.

    Let X=(A+B)X = (A+B). Then the expression becomes X(C+D)X(C+D).
    Applying the left distributive property, X(C+D)=XC+XDX(C+D) = XC + XD.

  2. Substitute X=(A+B)X = (A+B) back into the expression.

    XC+XD=(A+B)C+(A+B)DXC + XD = (A+B)C + (A+B)D
  3. Apply the right distributive property to each term.

    (A+B)C=AC+BC(A+B)C = AC + BC (A+B)D=AD+BD(A+B)D = AD + BD
  4. Combine the results.

    (A+B)(C+D)=AC+BC+AD+BD(A+B)(C+D) = AC + BC + AD + BD

    Since matrix addition is commutative, the order of terms in a sum does not matter.
    Therefore, AC+BC+AD+BD=AC+AD+BC+BDAC + BC + AD + BD = AC + AD + BC + BD.
    Proven\boxed{\text{Proven}}

    7. If the matrix A in Example 5 had all its four elements nonzero, would x′Axx'Ax still give a weighted sum of squares? Would the associative law still apply?

    To answer this, we assume xx is a column vector, and AA is a 2×22 \times 2 matrix. Let x=[x1x2]x = \begin{bmatrix} x_1 \\ x_2 \end{bmatrix} and A=[a11a12a21a22]A = \begin{bmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{bmatrix}.
    Then x′Ax=a11x12+(a12+a21)x1x2+a22x22x'Ax = a_{11}x_1^2 + (a_{12}+a_{21})x_1 x_2 + a_{22}x_2^2.

    • Would x′Axx'Ax still give a weighted sum of squares? If all four elements of AA are nonzero, then a12a_{12} and a21a_{21} are nonzero. This means the term (a12+a21)x1x2(a_{12}+a_{21})x_1 x_2 will generally be present (unless a12=−a21a_{12} = -a_{21}). A "weighted sum of squares" typically refers to a sum of terms of the form wixi2w_i x_i^2, without cross-product terms like x1x2x_1 x_2. Therefore, if AA is not a diagonal matrix (i.e., a12a_{12} or a21a_{21} are nonzero), x′Axx'Ax would be a quadratic form but not strictly a "weighted sum of squares" in the sense of only squared terms. ❌ No, it would generally be a quadratic form with cross-product terms, not solely a weighted sum of squares.

    • Would the associative law still apply? The associative law of matrix multiplication, (X′A)X=X′(AX)(X'A)X = X'(AX), applies whenever the matrix dimensions are compatible for multiplication. The values of the elements (zero or nonzero) do not affect the validity of the associative law itself. ✅ Yes, the associative law of matrix multiplication always applies when the dimensions are compatible.

    8. Name some situations or contexts where the notion of a weighted or unweighted sum of squares may be relevant.

    • Least Squares Regression: In statistics, this method minimizes the unweighted sum of squared residuals to find the best-fitting line or curve for a set of data points.
    • Weighted Least Squares (WLS): An extension of least squares where different data points are given different importance (weights) in the minimization process, leading to a weighted sum of squared residuals. This is used when observations have varying precision.
    • Variance and Standard Deviation: These fundamental statistical measures are based on the sum of squared differences from the mean, representing the spread of data.
    • Error Analysis and Measurement: When combining multiple measurements with different levels of uncertainty, a weighted sum of squares can be used to determine the most probable value, giving more weight to more precise measurements.
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