Here's the solution for 1.2:
1.2 Determine the equation of BE in the form y=mx+c.
Step 1: Use the gradient mBE=41 from 1.1.
Step 2: Substitute the gradient and one of the points on BE, for example E(12;0), into the equation y=mx+c.
0=41(12)+c
0=3+c
c=−3
Step 3: Write the equation of the line.
y=41x−3
The equation of BE is y=41x−3.
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