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Use the methods you discovered in 2.2 and 3.2 and simplify the following: 4.1.1 (x−3)(x+5)= 4.1.2 (x-9)2=

Mathematics

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Here are the solutions for the given algebraic expressions:

4.1 Use the methods you discovered in 2.2 and 3.2 and simplify the following:

4.1.1 (x−3)(x+5)(x-3)(x+5)

  1. Multiply the first terms of each binomial.

    x×x=x2x \times x = x^2

  2. Multiply the outer terms.

    x×5=5xx \times 5 = 5x

  3. Multiply the inner terms.

    −3×x=−3x-3 \times x = -3x

  4. Multiply the last terms of each binomial.

    −3×5=−15-3 \times 5 = -15

  5. Combine all terms and simplify by adding like terms.

    x2+5x−3x−15=x2+2x−15x^2 + 5x - 3x - 15 = x^2 + 2x - 15 \boxed{\text{x^2 + 2x - 15}}

    4.1.2 (x−9)2(x-9)^2

  6. Square the first term.

    x2x^2

  7. Multiply 2 by the product of the two terms in the bracket.

    2×x×(−9)=−18x2 \times x \times (-9) = -18x

  8. Square the last term.

    (−9)2=81(-9)^2 = 81

  9. Write the answer by combining the terms.

    x2−18x+81x^2 - 18x + 81 \boxed{\text{x^2 - 18x + 81}}
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