Use trigonometric ratios to find the size of the angle marked θ and β in each of the following right-angled triangles.

Mathematics
Use trigonometric ratios to find the size of the angle marked θ and β in each of the following right-angled triangles.

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Here are the solutions for finding the angles θ\theta and β\beta in each right-angled triangle.

2. Use trigonometric ratios to find the size of the angle marked θ\theta and β\beta in each of the following right-angled triangles.

a) For the first triangle: Step 1: To find θ\theta, use the tangent ratio, as the opposite and adjacent sides are given. tan(θ)=oppositeadjacent\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} tan(θ)=5 cm8 cm\tan(\theta) = \frac{5 \text{ cm}}{8 \text{ cm}} θ=arctan(58)\theta = \arctan\left(\frac{5}{8}\right) θ32.0\theta \approx 32.0^\circ Step 2: To find β\beta, use the property that the sum of the acute angles in a right-angled triangle is 9090^\circ. β=90θ\beta = 90^\circ - \theta β=9032.0\beta = 90^\circ - 32.0^\circ β58.0\beta \approx 58.0^\circ The angles are: θ32.0,β58.0\boxed{\theta \approx 32.0^\circ, \beta \approx 58.0^\circ}

b) For the second triangle: Step 1: To find θ\theta, use the sine ratio, as the opposite side and hypotenuse are given. sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} sin(θ)=4 cm10 cm\sin(\theta) = \frac{4 \text{ cm}}{10 \text{ cm}} sin(θ)=0.4\sin(\theta) = 0.4 θ=arcsin(0.4)\theta = \arcsin(0.4) θ23.6\theta \approx 23.6^\circ Step 2: To find β\beta, use the property that the sum of the acute angles in a right-angled triangle is 9090^\circ. β=90θ\beta = 90^\circ - \theta β=9023.6\beta = 90^\circ - 23.6^\circ β66.4\beta \approx 66.4^\circ The angles are: θ23.6,β66.4\boxed{\theta \approx 23.6^\circ, \beta \approx 66.4^\circ}

c) For the third triangle: Step 1: To find θ\theta, use the sine ratio, as the opposite side and hypotenuse are given. sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} sin(θ)=16 cm25 cm\sin(\theta) = \frac{16 \text{ cm}}{25 \text{ cm}} sin(θ)=0.64\sin(\theta) = 0.64 θ=arcsin(0.64)\theta = \arcsin(0.64) θ39.8\theta \approx 39.8^\circ Step 2: To find β\beta, use the property that the sum of the acute angles in a right-angled triangle is 9090^\circ. β=90θ\beta = 90^\circ - \theta β=9039.8\beta = 90^\circ - 39.8^\circ β50.2\beta \approx 50.2^\circ The angles are: θ39.8,β50.2\boxed{\theta \approx 39.8^\circ, \beta \approx 50.2^\circ}

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