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Using mathematical tables, calculate (364.6)3 and (0.6492)2.

Mathematics

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Answers

2 parts
i
48,470,000
ii
0.4213

Step-by-step solution

6 steps

Here are the calculations using mathematical tables:

Part i· 3 steps

Calculate (364.6)3(364.6)^3

Let X=(364.6)3X = (364.6)^3.

  1. Find the logarithm of 364.6.

    The characteristic of log⁡(364.6)\log(364.6) is 2 (since there are 3 digits before the decimal point, 3−1=23-1=2).
    From the logarithm table, the mantissa for 364 is 5611.
    The mean difference for 6 is 7.
    So, the mantissa for 364.6 is 5611+7=56185611 + 7 = 5618.

    log⁡(364.6)=2.5618\log(364.6) = 2.5618
  2. Multiply the logarithm by 3.

    log⁡X=3×log⁡(364.6)\log X = 3 \times \log(364.6) log⁡X=3×2.5618\log X = 3 \times 2.5618 log⁡X=7.6854\log X = 7.6854
  3. Find the antilogarithm of 7.6854.

    The characteristic is 7, so the number will have 7+1=87+1=8 digits before the decimal point.
    From the antilogarithm table, the antilog of 0.685 is 4.842.
    The mean difference for 4 is 5.
    So, the antilog of 0.6854 is 4.842+0.005=4.8474.842 + 0.005 = 4.847.

    X=4.847×107X = 4.847 \times 10^7 X=48,470,000X = 48,470,000

    The value is 48,470,000\boxed{48,470,000}.

Part ii0.4213

Calculate (0.6492)2(0.6492)^2

Let Y=(0.6492)2Y = (0.6492)^2.

  1. Find the logarithm of 0.6492.

    The characteristic of log⁡(0.6492)\log(0.6492) is 1ˉ\bar{1} (since there is one zero immediately after the decimal point, 0−1=−10-1=-1).
    From the logarithm table, the mantissa for 649 is 8122.
    The mean difference for 2 is 1.
    So, the mantissa for 0.6492 is 8122+1=81238122 + 1 = 8123.

    log⁡(0.6492)=1ˉ.8123\log(0.6492) = \bar{1}.8123
  2. Multiply the logarithm by 2.

    log⁡Y=2×log⁡(0.6492)\log Y = 2 \times \log(0.6492) log⁡Y=2×(1ˉ+0.8123)\log Y = 2 \times (\bar{1} + 0.8123) log⁡Y=−2+1.6246\log Y = -2 + 1.6246 log⁡Y=−1+0.6246\log Y = -1 + 0.6246 log⁡Y=1ˉ.6246\log Y = \bar{1}.6246
  3. Find the antilogarithm of 1ˉ.6246\bar{1}.6246.

    The characteristic is 1ˉ\bar{1}, so the number will have one zero before the first non-zero digit.
    From the antilogarithm table, the antilog of 0.624 is 4.207.
    The mean difference for 6 is 6.
    So, the antilog of 0.6246 is 4.207+0.006=4.2134.207 + 0.006 = 4.213.

    Y=0.4213Y = 0.4213

    The value is 0.4213\boxed{0.4213}.

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