Find the value of x in the given figure, where angles are 25°, 20°, x and 87°.

Label the triangle $\triangle ABC$ where $\angle ABC = 25^\circ$ (bottom left) and $\angle ACB = 87^\circ$ (bottom right).

$$\angle BAC = 180^\circ - 25^\circ - 87^\circ$$ $$\angle BAC = 68^\circ$$

$x$ (adjacent to side $AB$) and $20^\circ$ (adjacent to side $AC$).

$$x + 20^\circ = 68^\circ$$

$$x = 68^\circ - 20^\circ$$ $$x = 48^\circ$$

Final answer: $\boxed{48^\circ}$