Find the values of x and y in the given diagram.

The sum of the interior angles in a triangle is $180^\circ$.

$$41^\circ + 92^\circ + y = 180^\circ$$ $$133^\circ + y = 180^\circ$$

Subtract $133^\circ$ from both sides:

$$y = 180^\circ - 133^\circ$$ $$y = 47^\circ$$

Angles on a straight line sum to $180^\circ$. The angle $92^\circ$ and angle $x$ form a linear pair.

$$92^\circ + x = 180^\circ$$

Subtract $92^\circ$ from both sides:

$$x = 180^\circ - 92^\circ$$ $$x = 88^\circ$$

The values are:
$x = \boxed{\text{88}^\circ}$
$y = \boxed{\text{47}^\circ}$