Solve when P=45.28 ×(1.346)^ t

Mathematics

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Answer

82\text{82}

Step-by-step solution

4 steps

Calister, unaendelea na swali la kwanza lakini kwa namba tofauti. Nitachukulia unataka kukokotoa PP wakati t=2t=2, kama ilivyokuwa kwenye swali la awali.

Swali:
Tunapewa formula ya idadi ya samaki PP baada ya miaka tt:

P=45.28×(1.346)tP = 45.28 \times (1.346)^t

Tunahitaji kukokotoa idadi ya samaki wakati t=2t=2 na kutoa jibu la mwisho kwa nambari nzima iliyo karibu.

  1. Badilisha thamani ya t=2t=2 kwenye formula.

    P=45.28×(1.346)2P = 45.28 \times (1.346)^2
  2. Tumia logariti kurahisisha hesabu.

    Chukua logariti ya pande zote mbili:

    log⁡P=log⁡(45.28×(1.346)2)\log P = \log (45.28 \times (1.346)^2)

    Tumia sheria za logariti log⁡(ab)=log⁡a+log⁡b\log(ab) = \log a + \log b na log⁡(an)=nlog⁡a\log(a^n) = n \log a:

    log⁡P=log⁡45.28+log⁡(1.346)2\log P = \log 45.28 + \log (1.346)^2 log⁡P=log⁡45.28+2log⁡1.346\log P = \log 45.28 + 2 \log 1.346

    Kutoka kwenye jedwali la logariti (au kikokotoo):
    log⁡45.28≈1.6559\log 45.28 \approx 1.6559
    log⁡1.346≈0.1290\log 1.346 \approx 0.1290
    Badilisha thamani hizi:

    log⁡P=1.6559+2×0.1290\log P = 1.6559 + 2 \times 0.1290 log⁡P=1.6559+0.2580\log P = 1.6559 + 0.2580 log⁡P=1.9139\log P = 1.9139
  3. Tafuta antilogariti ili kupata thamani ya PP.

    P=antilog(1.9139)P = \text{antilog}(1.9139) P≈82.02P \approx 82.02
  4. Zungusha jibu la mwisho kwa nambari nzima iliyo karibu.

    Idadi ya samaki ni takriban 82.

    Jibu la mwisho ni:

    82\text{82}
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