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Solve for t in the equation K = m sqrt((t-p)/(m))

Mathematics

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Answer

t=K2+mpmt = \frac{K^2 + mp}{m}

Step-by-step solution

6 steps

Your steps are mostly correct, but there is an error in one line that leads to an incorrect final answer.

Here's a breakdown of the correct steps:

Given the equation:

K=mt−pmK = m \sqrt{\frac{t-p}{m}}
  1. Divide both sides by mm.

    Km=t−pm\frac{K}{m} = \sqrt{\frac{t-p}{m}}
  2. Square both sides to eliminate the square root.

    (Km)2=(t−pm)2\left(\frac{K}{m}\right)^2 = \left(\sqrt{\frac{t-p}{m}}\right)^2 K2m2=t−pm\frac{K^2}{m^2} = \frac{t-p}{m}
  3. Multiply both sides by m2m^2 to clear the denominators.

    Your step K2=m2t−m2pK^2 = m^2 t - m^2 p is incorrect. When you multiply t−pm\frac{t-p}{m} by m2m^2, one mm in the numerator cancels with the mm in the denominator.

    m2⋅K2m2=m2⋅t−pmm^2 \cdot \frac{K^2}{m^2} = m^2 \cdot \frac{t-p}{m} K2=m(t−p)K^2 = m(t-p)
  4. Distribute mm on the right side.

    K2=mt−mpK^2 = mt - mp
  5. Add mpmp to both sides to isolate the term containing tt.

    K2+mp=mtK^2 + mp = mt
  6. Divide both sides by mm to solve for tt.

    K2+mpm=t\frac{K^2 + mp}{m} = t

    The correct final answer is:

    t=K2+mpmt = \frac{K^2 + mp}{m}
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