Without using logarithms or calculator evaluate: 2 5 - 3 2 + 32

I will solve questions 7, 8, and 9. For questions 7 and 8, where the base of the logarithm is not specified, I will assume a common logarithm (base 10), as is standard practice when "log" is written without a subscript.

Question 7:
Without using logarithms or calculator evaluate: $2\log 5 - 3\log 2 + \log 32$

Step 1: Apply the power rule of logarithms, $a \log b = \log b^a$.

$$2\log 5 = \log 5^2 = \log 25$$ $$$$