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Calculate the z-score and determine if the data point 250 is an outlier, given a mean of 81 and a standard deviation of 130.

Mathematics

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Answer

not outlier\text{not outlier}

Step-by-step solution

3 steps
  1. Identify the given values.

    Mean (μ\mu) =81= 81
    Standard deviation (σ\sigma) =130= 130
    Data point (xx) =250= 250

  2. Calculate the z-score for the data point.

    The z-score measures how many standard deviations a data point is from the mean. The formula is:

    z=x−μσz = \frac{x - \mu}{\sigma}

    Substitute the given values:

    z=250−81130z = \frac{250 - 81}{130} z=169130z = \frac{169}{130} z=1.3z = 1.3
  3. Determine if the data point is an outlier.

    A common rule for identifying outliers is that a data point is considered an outlier if its absolute z-score is greater than 2 or 3.

    • If ∣z∣>2|z| > 2, it's often considered an outlier.
    • If ∣z∣>3|z| > 3, it's generally considered a strong outlier. In this case, the calculated z-score is 1.3. Since ∣1.3∣|1.3| is less than 2 (and also less than 3), the data point is not considered an outlier.

    The final answer is not outlier\text{not outlier}.

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