1. The dimensions of magnetic field are
This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Here are the solutions to the questions:
1. The dimensions of magnetic field are
The magnetic force $F$ on a charge $q$ moving with velocity $v$ in a magnetic field $B$ is given by $F = qvB\sin\theta$.
Rearranging for $B$, we get $B = \frac{F}{qv}$.
The dimensions of force $F$ are $\text{MLT}^{-2}$.
The dimensions of charge $q$ are $\text{IT}$ (current $\times$ time).
The dimensions of velocity $v$ are $\text{LT}^{-1}$.
Substituting these into the equation for $B$:
$$[B] = \
