The dimensions of magnetic field are

Here are the solutions to the questions:

1. The dimensions of magnetic field are

• The magnetic force $F$ on a charge $q$ moving with velocity $v$ in a magnetic field $B$ is given by $F = qvB\sin\theta$.
• Rearranging for $B$, we get $B = \frac{F}{qv}$.
• The dimensions of force $F$ are $\text{MLT}^{-2}$.
• The dimensions of charge $q$ are $\text{IT}$ (current $\times$ time).
• The dimensions of velocity $v$ are $\text{LT}^{-1}$.
• Substituting these into the equation for $B$: $$$$