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A 60 kg object is to be accelerated vertically upwards at 10 m/s2. Calculate the upward force needed to achieve this. (g = 10 m/s2)

Physics

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Answer

B) 1,200N\text{B) } 1,200\text{N}

Step-by-step solution

5 steps

B)

  1. Identify the given values.

    The mass of the object is m=60m = 60 kg.
    The desired acceleration is a=10a = 10 m s−2^{-2} vertically upwards.
    The acceleration due to gravity is g=10g = 10 m s−2^{-2}.

  2. Determine the forces acting on the mass.

    There are two main forces acting on the mass:

    • The gravitational force (weight) acting downwards: Fg=mgF_g = mg.
    • The applied force acting upwards: FappliedF_{applied}.
  3. Calculate the gravitational force.

    Fg=mg=(60 kg)(10 m s−2)=600 NF_g = mg = (60 \text{ kg})(10 \text{ m s}^{-2}) = 600 \text{ N}
  4. Apply Newton's Second Law.

    The net force (FnetF_{net}) required to accelerate the mass upwards is the sum of the applied force and the gravitational force (considering direction). Since the acceleration is upwards, the applied force must overcome gravity.

    Fnet=Fapplied−FgF_{net} = F_{applied} - F_g

    Also, according to Newton's Second Law, Fnet=maF_{net} = ma.
    So,

    ma=Fapplied−Fgma = F_{applied} - F_g
  5. Solve for the applied force.

    Rearrange the equation to solve for FappliedF_{applied}:

    Fapplied=ma+FgF_{applied} = ma + F_g

    Substitute the values:

    Fapplied=(60 kg)(10 m s−2)+600 NF_{applied} = (60 \text{ kg})(10 \text{ m s}^{-2}) + 600 \text{ N} Fapplied=600 N+600 NF_{applied} = 600 \text{ N} + 600 \text{ N} Fapplied=1200 NF_{applied} = 1200 \text{ N}

    The force that has to be exerted is 1200 N.

    The final answer is B) 1,200N\text{B) } 1,200\text{N}.

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