This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Hey — ready when you are. 1. C) Displacement Displacement is a vector quantity because it has both magnitude and direction. Speed, work, and energy are scalar quantities, possessing only magnitude. 2. To find the time it takes for the ball to return to the thrower, we first find the time it takes to reach its maximum height. At the maximum height, the final velocity is 0 m/s. Given: Initial velocity, u = 20 m/s Acceleration due to gravity, a = -g = -10 m/s^2 (negative because it opposes upward motion) Final velocity at max height, v = 0 m/s Step 1: Calculate time to reach maximum height (t_up). Using the kinematic equation v = u + at: 0 = 20 + (-10)t_up 10t_up = 20 t_up = (20)/(10) t_up = 2 s Step 2: Calculate total time to return to the thrower. The time to go up is equal to the time to come down. Total time, T = 2 × t_up T = 2 × 2 s T = 4 s The correct option is B. The final answer is 4 s. 3. Given: Velocity Ratio (VR) = 5 Efficiency () = 80\% = 0.8 Step 1: Recall the formula for efficiency in terms of Mechanical Advantage (MA) and Velocity Ratio (VR). = MAVR Step 2: Rearrange the formula to solve for Mechanical Advantage (MA). MA = × VR Step 3: Substitute the given values and calculate MA. MA = 0.8 × 5 MA = 4.0 The correct option is C. The final answer is 4.0. 4. Given: Mass, m = 10 kg Velocity, v = 5 m/s Step 1: Recall the formula for kinetic energy (KE). KE = (1)/(2)mv^2 Step 2: Substitute the given values into the formula. KE = (1)/(2)(10 kg)(5 m/s)^2 Step 3: Calculate the kinetic energy. KE = (1)/(2)(10 kg)(25 m^2/s^2) KE = 5 × 25 J KE = 125 J The correct option is C. The final answer is 125 J. Send me the next one 📸