A body starts from rest and moves with uniform acceleration. If its velocity after 5 seconds is 20 m/s, what is the acceleration and the distance covered in 5 seconds?

The image provided is very difficult to read due to its low quality and blurriness. Based on the visible words and common problem structures, I will assume the question is: "A body starts from rest and moves with uniform acceleration. If its velocity after 5 seconds is 20 m/s, what is the acceleration and the distance covered in 5 seconds?" Here's the solution based on this assumption: Given: Initial velocity (u) = 0 m/s (starts from rest) Time (t) = 5 s Final velocity (v) = 20 m/s We need to find: Acceleration (a) Distance covered (s) Step 1: Calculate the acceleration (a). We use the first equation of motion: v = u + at. 20 m/s = 0 m/s + a × 5 s 20 = 5a a = (20)/(5) a = 4 m/s^2 The acceleration is 4 m/s^2. Step 2: Calculate the distance covered (s). We use the second equation of motion: s = ut + (1)/(2)at^2. s = (0 m/s)(5 s) + (1)/(2)(4 m/s^2)(5 s)^2 s = 0 + (1)/(2)(4)(25) s = 2 × 25 s = 50 m The distance covered is 50 m. Send me the next one 📸