We read your photo as:

A) Calculate the effective resistance of bulbs A and B. b) Switch S is now closed for a short time. Determine the reading on: Voltmeter V1, Voltmeter V3

Physics

ScanSolve AI Answer

Step-by-step solution

11 steps

Part 1

Part a· 3 steps

Calculate the effective resistance of bulbs A and B.

  1. Identify the connection type and resistances.

    Bulbs A and B are connected in parallel.
    Resistance of bulb A, RA=2 ΩR_A = 2 \, \Omega.
    Resistance of bulb B, RB=2 ΩR_B = 2 \, \Omega.

  2. Use the formula for parallel resistors.

    1RAB=1RA+1RB\frac{1}{R_{AB}} = \frac{1}{R_A} + \frac{1}{R_B}

  3. Substitute the values and calculate RABR_{AB}.

    1RAB=12 Ω+12 Ω\frac{1}{R_{AB}} = \frac{1}{2 \, \Omega} + \frac{1}{2 \, \Omega} 1RAB=22 Ω\frac{1}{R_{AB}} = \frac{2}{2 \, \Omega} 1RAB=11 Ω\frac{1}{R_{AB}} = \frac{1}{1 \, \Omega} RAB=1 ΩR_{AB} = 1 \, \Omega

    The effective resistance of bulbs A and B is 1 Ω\boxed{\text{}1 \, \Omega\text{}}

Part b· 5 steps

Switch S is now closed for a short time. Determine the reading on

  • Voltmeter V1

  1. Identify what V1 measures.

    Voltmeter V1 measures the total electromotive force (EMF) of the battery.
    There are 4 cells connected in series, and each cell has an EMF of 1.5 V.

  2. Calculate the total EMF.

    Total EMF=4×1.5 V=6 V\text{Total EMF} = 4 \times 1.5 \, \text{V} = 6 \, \text{V}

    The reading on Voltmeter V1 is 6 V\boxed{\text{}6 \, \text{V}\text{}}

    • Voltmeter V3

  3. Calculate the total resistance of the circuit.

    The parallel combination of A and B (RAB=1 ΩR_{AB} = 1 \, \Omega) is in series with bulb C (RC=3 ΩR_C = 3 \, \Omega).

    Rtotal=RAB+RCR_{total} = R_{AB} + R_C Rtotal=1 Ω+3 Ω=4 ΩR_{total} = 1 \, \Omega + 3 \, \Omega = 4 \, \Omega

  4. Calculate the total current in the circuit.

    Using Ohm's Law, Itotal=Total EMFRtotalI_{total} = \frac{\text{Total EMF}}{R_{total}}.

    Itotal=6 V4 Ω=1.5 AI_{total} = \frac{6 \, \text{V}}{4 \, \Omega} = 1.5 \, \text{A}

  5. Calculate the voltage across bulb C (reading on V3).

    Using Ohm's Law, V3=Itotal×RCV_3 = I_{total} \times R_C.

    V3=1.5 A×3 Ω=4.5 VV_3 = 1.5 \, \text{A} \times 3 \, \Omega = 4.5 \, \text{V}

    The reading on Voltmeter V3 is 4.5 V\boxed{\text{}4.5 \, \text{V}\text{}}

Part c· 3 steps

Calculate the energy transferred in bulb C in 3 seconds if the current in the circuit is 2 A.

  1. Identify the given values.

    Current, I=2 AI = 2 \, \text{A}.
    Time, t=3 st = 3 \, \text{s}.
    Resistance of bulb C, RC=3 ΩR_C = 3 \, \Omega.

  2. Use the formula for energy transferred.

    E=I2RCtE = I^2 R_C t

  3. Substitute the values and calculate the energy.

    E=(2 A)2×3 Ω×3 sE = (2 \, \text{A})^2 \times 3 \, \Omega \times 3 \, \text{s} E=4 A2×3 Ω×3 sE = 4 \, \text{A}^2 \times 3 \, \Omega \times 3 \, \text{s} E=36 JE = 36 \, \text{J}

    The energy transferred in bulb C is $\boxed{36 ,

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question

More Physics Questions

QIn which way are bulb F and T connected in series? What is the reading on voltmeter V1? If voltmeter…QA circuit consists of four 1.5 V cells in series, and three bulbs A, B, and C. Bulbs A and B have…QTwo electric bulbs A and B rated 200 V – 100 W and 200 V – 60 W are connected in series to a 200 V…QA) (i) Name the meters A and V. (ii) Calculate the readings of meters A and V when the key K is…QSolve 3 (b) (i) Ammeter reading when key K is open.
See all Physics questions →
Got a syllabus? Photograph it and I'll tell you what's due and what's worth the most.
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp