We're asked to calculate the emf

September 4, 2026Physics

ScanSolve AI Answer

Answer

\text{7800 V}

4 steps

Okay, let's calculate the EMF.

Identify the given values from the image.
- Magnetic field strength, $B = 5.00 \times 10^{-5} \text{ T}$
- Velocity of the conductor, $V = 7.80 \times 10^3 \text{ m/s}$
- Length of the conductor, $L = 2.0 \times 10^4 \text{ m}$
State the formula for motional electromotive force (EMF).
The motional EMF ( $\epsilon$ ) induced in a conductor of length $L$ moving with velocity $V$ perpendicular to a magnetic field $B$ is given by:
$\epsilon = BlV$
Substitute the values into the formula.
$\epsilon = (5.00 \times 10^{-5} \text{ T}) \times (2.0 \times 10^4 \text{ m}) \times (7.80 \times 10^3 \text{ m/s})$
Calculate the EMF.
$\epsilon = (5.00 \times 2.0 \times 7.80) \times (10^{-5} \times 10^4 \times 10^3) \text{ V}$ $\epsilon = (10.0 \times 7.80) \times 10^{-5+4+3} \text{ V}$ $\epsilon = 78.0 \times 10^2 \text{ V}$ $\epsilon = 7800 \text{ V}$
The induced electromotive force (EMF) is $\text{7800 V}$ .

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