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A car is traveling at 30 m/s when the driver applies the brakes. The car comes to rest in 5 seconds. What is the deceleration of the car?

Physics

ScanSolve AI Answer

Answer

6 m/s2\text{6 m/s}^2

Step-by-step solution

4 steps
  1. Identify the given values.

    The initial velocity of the car is u=30 m/su = 30 \text{ m/s}.
    The car comes to rest, so the final velocity is v=0 m/sv = 0 \text{ m/s}.
    The time taken is t=5 st = 5 \text{ s}.

  2. Use the formula for acceleration.

    Acceleration aa is defined as the change in velocity over time:

    a=v−uta = \frac{v - u}{t}
  3. Substitute the values into the formula.

    a=0 m/s−30 m/s5 sa = \frac{0 \text{ m/s} - 30 \text{ m/s}}{5 \text{ s}} a=−30 m/s5 sa = \frac{-30 \text{ m/s}}{5 \text{ s}} a=−6 m/s2a = -6 \text{ m/s}^2
  4. Determine the deceleration.

    Deceleration is the magnitude of the negative acceleration.
    Therefore, the deceleration is 6 m/s26 \text{ m/s}^2.

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