A car of mass 1000kg moves in circular path radius of 50m at speed of 10m/s. Find its centripetal force

Question

ScanSolve AI Tutor · Accepted Answer

To find the centripetal force, we use the formula:

F_c = \frac{mv^2}{r}

Where:

Identify the given values.
$m = 1000 \text{ kg}$
$v = 10 \text{ m/s}$
$r = 50 \text{ m}$
Substitute the values into the formula.
$F_c = \frac{(1000 \text{ kg})(10 \text{ m/s})^2}{50 \text{ m}}$
Calculate the square of the speed.
$(10 \text{ m/s})^2 = 100 \text{ m}^2/\text{s}^2$
Perform the multiplication in the numerator.
$F_c = \frac{1000 \text{ kg} \times 100 \text{ m}^2/\text{s}^2}{50 \text{ m}}$ $F_c = \frac{100000 \text{ kg}\cdot\text{m}^2/\text{s}^2}{50 \text{ m}}$
Perform the division.
$F_c = 2000 \text{ kg}\cdot\text{m}/\text{s}^2$
Since $1 \text{ kg}\cdot\text{m}/\text{s}^2 = 1 \text{ N}$ (Newton), the force is:
$F_c = 2000 \text{ N}$
The centripetal force is $\text{2000 N}$ .

Answer