This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Welcome back Blaq_vortex👌👌 — missed you this week. Here are the solutions for question 12: a) Describe the motion of the graph at points: (i) R: The car is accelerating, but its acceleration is decreasing*. The speed is increasing, but the rate at which it increases is slowing down. (ii) S: The car is moving at a constant speed*. Its acceleration is zero. (iii) T: The car is decelerating (slowing down) at a constant rate*. Its acceleration is constant and negative. b) Determine the speed of the car at time = 4.0 s. Step 1: Locate t = 4.0 s on the time axis. Step 2: Read the corresponding speed value from the graph. At t = 4.0 s, the speed is 18 m/s. The speed of the car at t = 4.0 s is 18 m/s. c) Determine the distance moved by the car from time = 16.0 s to time = 20.0 s. The distance moved is the area under the speed-time graph. For the interval from t = 16.0 s to t = 20.0 s, the shape is a triangle. Step 1: Identify the coordinates at the start and end of the interval. At t_1 = 16.0 s, speed v_1 = 20 m/s. At t_2 = 20.0 s, speed v_2 = 0 m/s. Step 2: Calculate the base and height of the triangle. Base = t = t_2 - t_1 = 20.0 s - 16.0 s = 4.0 s. Height = v_1 = 20 m/s (since v_2 = 0). Step 3: Calculate the area of the triangle. Distance = (1)/(2) × base × height Distance = (1)/(2) × (4.0 s) × (20 m/s) Distance = 2 s × 20 m/s Distance = 40 m The distance moved by the car from t = 16.0 s to t = 20.0 s is 40 m. Send me the next one 📸