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A moving-coil instrument with a resistance of 5 and a full-scale deflection current of 20 mA is to be converted into an ammeter to measure a total current of 3 A. Calculate the required shunt resistan

Physics

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Answer

0.0336 Ω\text{0.0336 } \Omega

Step-by-step solution

5 steps
  1. Identify the given values.

    The resistance of the moving-coil instrument is Rm=5 ΩR_m = 5 \, \Omega.
    The full-scale deflection current of the instrument is Im=20 mA=0.020 AI_m = 20 \, \text{mA} = 0.020 \, \text{A}.
    The total current to be measured is I=3 AI = 3 \, \text{A}.

  2. Determine the current that must flow through the shunt resistor.

    When a shunt resistor is connected in parallel with the instrument, the total current II splits between the instrument current ImI_m and the shunt current IshI_{sh}.

    I=Im+IshI = I_m + I_{sh}

    Therefore, the current through the shunt resistor is:

    Ish=I−ImI_{sh} = I - I_m Ish=3 A−0.020 AI_{sh} = 3 \, \text{A} - 0.020 \, \text{A} Ish=2.98 AI_{sh} = 2.98 \, \text{A}
  3. Calculate the voltage across the instrument.

    Since the shunt resistor is in parallel with the instrument, the voltage across both components is the same.
    The voltage across the instrument is:

    Vm=Im×RmV_m = I_m \times R_m Vm=0.020 A×5 ΩV_m = 0.020 \, \text{A} \times 5 \, \Omega Vm=0.1 VV_m = 0.1 \, \text{V}
  4. Calculate the shunt resistance.

    The voltage across the shunt resistor is equal to the voltage across the instrument, Vsh=Vm=0.1 VV_{sh} = V_m = 0.1 \, \text{V}.
    Using Ohm's Law for the shunt resistor:

    Vsh=Ish×RshV_{sh} = I_{sh} \times R_{sh} Rsh=VshIshR_{sh} = \frac{V_{sh}}{I_{sh}} Rsh=0.1 V2.98 AR_{sh} = \frac{0.1 \, \text{V}}{2.98 \, \text{A}} Rsh≈0.033557 ΩR_{sh} \approx 0.033557 \, \Omega
  5. Round the final answer.

    Rsh≈0.0336 ΩR_{sh} \approx 0.0336 \, \Omega

    The shunt resistance required is 0.0336 Ω\text{0.0336 } \Omega.

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