What is a Rigid body? Find the Centre of mass of 3 particles at the edge of an equilateral triangle with masses 50g, 75g and 100g respectively, each side of the triangle is 5m long.

Alright Adeyemi — let's do this. Here are the solutions to your questions: 1. What is a Rigid body? A rigid body is an idealized solid object that does not deform under the action of external forces. This means that the distance between any two particles within the body remains constant, regardless of the forces applied to it. 2. Find the Centre of mass of 3 particles at the edge of an equilateral triangle with masses 50g, 75g and 100g respectively, each side of the triangle is 5m long. Step 1: Assign coordinates to each particle. Let the side length of the equilateral triangle be L = 5 \, m. We place the first particle at the origin. • Particle 1 (m_1 = 50 \, g) at (x_1, y_1) = (0, 0). • Particle 2 (m_2 = 75 \, g) at (x_2, y_2) = (L, 0) = (5, 0). • Particle 3 (m_3 = 100 \, g) at (x_3, y_3) = ((L)/(2), Lsqrt(3)2) = ((5)/(2), 5sqrt(3)2). Step 2: Calculate the total mass (M_total). M_total = m_1 + m_2 + m_3 = 50 \, g + 75 \, g + 100 \, g = 225 \, g Step 3: Calculate the x-coordinate of the center of mass (X_CM). The formula for X_CM is ( m_i x_i)/( m_i). m_i x_i = (50 \, g)(0 \, m) + (75 \, g)(5 \, m) + (100 \, g)((5)/(2) \, m) m_i x_i = 0 + 375 \, g · m + 250 \, g · m = 625 \, g · m X_CM = 625 \, g · m225 \, g = (25)/(9) \, m Step 4: Calculate the y-coordinate of the center of mass (Y_CM). The formula for Y_CM is ( m_i y_i)/( m_i). m_i y_i = (50 \, g)(0 \, m) + (75 \, g)(0 \, m) + (100 \, g)(5sqrt(3)2 \, m) m_i y_i = 0 + 0 + 250sqrt(3) \, g · m = 250sqrt(3) \, g · m Y_CM = 250sqrt(3) \, g · m225 \, g = 10sqrt(3)9 \, m Step 5: State the coordinates of the center of mass. The center of mass is (X_CM, Y_CM). ((25)/(9) \, m, 10sqrt(3)9 \, m) Send me the next one 📸