A simple harmonic oscillator a time period of 10s, write an equation relates it's acceleration and displacement x

Physics

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Answer

a=π225xa = -\frac{\pi^2}{25} x

Step 1: The general equation for acceleration aa in simple harmonic motion (SHM) is given by: a=ω2xa = -\omega^2 x where ω\omega is the angular frequency and xx is the displacement.

Step 2: Calculate the angular frequency ω\omega using the given time period T=10T = 10 s. ω=2πT\omega = \frac{2\pi}{T} ω=2π10s\omega = \frac{2\pi}{10 s} ω=π5 rad/s\omega = \frac{\pi}{5} \text{ rad/s}

Step 3: Substitute the value of ω\omega into the acceleration equation. a=(π5)2xa = -\left(\frac{\pi}{5}\right)^2 x a=π225xa = -\frac{\pi^2}{25} x

The equation relating acceleration and displacement is: a=π225x\boxed{a = -\frac{\pi^2}{25} x} Send me the next one 📸

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Quick Answer

The general equation for acceleration a in simple harmonic motion (SHM) is given by: a = -^2 x where is the angular frequency and x is the displacement.

A simple harmonic oscillator a time period of 10s, write an equation relates it's acceleration and displacement x
Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI Answer
Step 1: The general equation for acceleration a in simple harmonic motion (SHM) is given by: a = -^2 x where is the angular frequency and x is the displacement. Step 2: Calculate the angular frequency using the given time period T = 10 s. = (2)/(T) = (2)/(10 s) = ()/(5) rad/s Step 3: Substitute the value of into the acceleration equation. a = -(()/(5))^2 x a = -(^2)/(25) x The equation relating acceleration and displacement is: a = -(^2)/(25) x Send me the next one 📸