A simple pendulum experiment is conducted. Given t1 and t2 values for 20 oscillations at l=50 cm, calculate T and T2.

April 13, 2026Physics

ScanSolve AI Answer

April 13, 2026

Answer

50$ cm.

Step 1: Prepare the data for plotting. The period $T$ for a simple pendulum is given by $T = \frac{Mean t}{20}$ , where Mean $t$ is the average time for 20 oscillations. The length $l$ must be in meters. We will calculate $T$ and $T^2$ using the provided $t_1$ and $t_2$ values.

First, let's correct the Mean $t$ for $l=50$ cm. For $l=50$ cm: $t_1 = 29.00$ s, $t_2 = 28.60$ s. Mean $t = \frac{29.00

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Prepare the data for plotting. The period T for a simple pendulum is given by T = Mean t20, where Mean t is the average time for 20 oscillations.

Asked on April 13, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on April 13, 2026

Step 1: Prepare the data for plotting. The period T for a simple pendulum is given by T = Mean t20, where Mean t is the average time for 20 oscillations. The length l must be in meters. We will calculate T and T^2 using the provided t_1 and t_2 values. First, let's correct the Mean t for l=50 cm. For l=50 cm: t_1 = 29.00 s, t_2 = 28.60 s. Mean $t = 29.00