This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Step 1: Calculate the time of flight (t). The horizontal motion of the stone is uniform, meaning its horizontal velocity remains constant. We use the formula: Horizontal distance = Horizontal velocity × Time Given: Horizontal distance (R) = 50 m Horizontal velocity (u_x) = 10 m/s R = u_x t 50 m = (10 m/s) t t = 50 m10 m/s t = 5 s Step 2: Calculate the height of the building (h). The vertical motion of the stone is under constant acceleration due to gravity. The initial vertical velocity is 0 m/s because the stone is thrown horizontally. We use the kinematic equation: h = u_y t + (1)/(2) g t^2 Given: Initial vertical velocity (u_y) = 0 m/s Acceleration due to gravity (g) = 10 m/s^2 (as indicated in the student's work) Time (t) = 5 s h = (0 m/s)(5 s) + (1)/(2) (10 m/s^2) (5 s)^2 h = 0 + (1)/(2) (10 m/s^2) (25 s^2) h = (5 m/s^2) (25 s^2) h = 125 m The height of the building is 125 m.