A TV draws 0.7 A from a 220 V supply. Calculate the energy transfer if the TV is switched on for 4 hours.

$$
P = 220\, \text{V} \times 0.7\, \text{A}
$$
$$
P = 154\, \text{W}
$$

$$
t = 4\, \text{hours} \times \frac{60\, \text{min}}{1\, \text{hour}} \times \frac{60\, \text{s}}{1\, \text{min}}
$$
$$
t = 14400\, \text{s}
$$

$$
E = 154\, \text{W} \times 14400\, \text{s}
$$
$$
E = 2217600\, \text{J}
$$
The energy transfer is $\boxed{\text{2217600 J}}$.

$$
t = 10\, \text{min} \times \frac{60\, \text{s}}{1\, \text{min}}
$$
$$
t = 600\, \text{s}
$$

$$
P = \frac{9 \times 10^3\, \text{J}}{600\, \text{s}}
$$
$$
P = \frac{9000\, \text{J}}{600\, \text{s}}
$$
$$
P = 15\, \text{W}
$$
The power output of the motor is $\boxed{\text{15 W}}$.