An Air Force jet flying with a speed of 335m/s went past an anti-aircraft gun. How far is the aircraft 5s later when the gun was fired

Physics

ScanSolve AI Answer

Answer

1675 m\text{1675 m}

Step-by-step solution

3 steps
  1. Identify the given values.

    The speed of the aircraft is v=335 m/sv = 335 \text{ m/s}.
    The time elapsed is t=5 st = 5 \text{ s}.

  2. Use the formula for distance.

    The distance dd covered by an object moving at a constant speed is given by the formula:

    d=v×td = v \times t
  3. Substitute the values and calculate the distance.

    d=335 m/s×5 sd = 335 \text{ m/s} \times 5 \text{ s} d=1675 md = 1675 \text{ m}

    The aircraft is 1675 m\boxed{\text{1675 m}} away.

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