This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here are the calculations for the concave mirror: a) Calculate the magnification of the image. Step 1: Use the mirror formula to find the image distance (v). The mirror formula is (1)/(f) = (1)/(u) + (1)/(v), where f is the focal length, u is the object distance, and v is the image distance. For a concave mirror, f is positive. Given: f = 10 cm, u = 15 cm. (1)/(10 cm) = (1)/(15 cm) + (1)/(v) (1)/(v) = (1)/(10 cm) - (1)/(15 cm) (1)/(v) = (3)/(30 cm) - (2)/(30 cm) (1)/(v) = (1)/(30 cm) v = 30 cm Step 2: Calculate the magnification (M). The magnification formula is M = -(v)/(u). M = -30 cm15 cm M = -2 The magnification of the image is -2. b) Calculate the height of the image. Step 3: Use the magnification formula M = (h_i)/(h_o) to find the height of the image (h_i). Given: h_o = 3 cm, M = -2. -2 = (h_i)/(3 cm) h_i = -2 × 3 cm h_i = -6 cm The height of the image is -6 cm. The negative sign indicates that the image is inverted. c) Is the image magnified or diminished? Explain your answer. Step 4: Compare the absolute value of the magnification or image height to determine if the image is magnified or diminished. The absolute value of the magnification is |M| = |-2| = 2. Since |M| > 1, the image is magnified. Alternatively, the absolute height of the image is |h_i| = |-6 cm| = 6 cm, which is greater than the object height h_o = 3 cm. Therefore, the image is magnified. Send me the next one 📸