An object on the end of a spring oscillates with SHM of regular frequency 2.0rads, what is the period of the oscillation

June 18, 2026Physics

ScanSolve AI Answer

June 18, 2026

Answer

3.14 s

Step 1: Identify the relationship between angular frequency and period. The period $T$ of an oscillation is related to its angular frequency $\omega$ by the formula: $T = \frac{2\pi}{\omega}$

Step 2: Substitute the given angular frequency into the formula. Given $\omega = 2.0 \text{ rad/s}$ . $T = \frac{2\pi}{2.0 rad/s}$

Step 3: Calculate the period. $T = \pi \text{ s}$ Using $\pi \approx 3.14159$ : $T \approx 3.14 \text{ s}$

The period of the oscillation is $\boxed{3.14 s}$ .

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Identify the relationship between angular frequency and period. The period T of an oscillation is related to its angular frequency by the formula: T = (2)/() Step 2: Substitute the given angular frequency into the formula.

Asked on June 18, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on June 18, 2026

Step 1: Identify the relationship between angular frequency and period. The period T of an oscillation is related to its angular frequency by the formula: T = (2)/() Step 2: Substitute the given angular frequency into the formula. Given = 2.0 rad/s. T = (2)/(2.0 rad/s) Step 3: Calculate the period. T = s Using ≈ 3.14159: T ≈ 3.14 s The period of the oscillation is 3.14 s. Send me the next one 📸