An object on the end of a spring oscillates with SHM of regular frequency 2.0rads, what is the period of the oscillation

Step 1: Identify the relationship between angular frequency and period. The period $T$ of an oscillation is related to its angular frequency $\omega$ by the formula: $T = \frac{2\pi}{\omega}$

Step 2: Substitute the given angular frequency into the formula. Given $\omega = 2.0 \text{ rad/s}$. $T = \frac{2\pi}{2.0 rad/s}$

Step 3: Calculate the period. $T = \pi \text{ s}$ Using $\pi \approx 3.14159$: $T \approx 3.14 \text{ s}$

The period of the oscillation is $\boxed{3.14 s}$.

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