An object on the end of a spring oscillates with SHM of regular frequency 2.0rads, what is the period of the oscillation

The period $T$ of an oscillation is related to its angular frequency $\omega$ by the formula:

$$T = \frac{2\pi}{\omega}$$

Given $\omega = 2.0 \text{ rad/s}$.

$$T = \frac{2\pi}{2.0 \text{ rad/s}}$$

$$T = \pi \text{ s}$$

Using $\pi \approx 3.14159$:

$$T \approx 3.14 \text{ s}$$

The period of the oscillation is $\text{3.14 s}$.