Analyze the data to provide the necessary information needed by the project manager and establish if the engineer can reach in time to deliver it. Explain how the device needed by the supervisor can be made and able to serve the purpose.

Nguvu ya msuguano inapinga mwendo wa gari.

$$F_f = \mu mg$$ $$F_f = 0.025 \times 2000 \text{ kg} \times 9.81 \text{ m/s}^2$$ $$F_f = 490.5 \text{ N}$$

Nguvu halisi inayofanya kazi wakati wa kuongeza kasi ni tofauti kati ya nguvu ya kusukuma na nguvu ya msuguano.

$$F_{net,1} = F_d - F_f$$ $$F_{net,1} = 1100 \text{ N} - 490.5 \text{ N}$$ $$F_{net,1} = 609.5 \text{ N}$$

Kuongeza kasi $a_1$ huhesabiwa kwa kutumia Sheria ya Pili ya Newton.

$$a_1 = \frac{F_{net,1}}{m}$$ $$a_1 = \frac{609.5 \text{ N}}{2000 \text{ kg}}$$ $$a_1 = 0.30475 \text{ m/s}^2$$

Kasi ya mwisho $v_1$ baada ya umbali $s_1 = 1200 \text{ m}$ (kutoka kasi ya awali $u_1 = 0 \text{ m/s}$) huhesabiwa kwa kutumia fomula ya kinematiki.

$$v_1^2 = u_1^2 + 2a_1s_1$$ $$v_1^2 = (0 \text{ m/s})^2 + 2(0.30475 \text{ m/s}^2)(1200 \text{ m})$$ $$v_1^2 = 731.4 \text{ (m/s)}^2$$ $$v_1 = \sqrt{731.4} \approx 27.044 \text{ m/s}$$

Muda $t_1$ wa awamu hii huhesabiwa kwa kutumia fomula ya kinematiki.

$$v_1 = u_1 + a_1t_1$$ $$t_1 = \frac{v_1 - u_1}{a_1}$$ $$t_1 = \frac{27.044 \text{ m/s} - 0 \text{ m/s}}{0.30475 \text{ m/s}^2}$$ $$t_1 \approx 88.74 \text{ s}$$

Gari huanza kupunguza kasi kutoka $u_2 = v_1 = 27.044 \text{ m/s}$ na inasimama ($v_2 = 0 \text{ m/s}$) baada ya umbali $s_2 = 500 \text{ m}$.
Kupunguza kasi $a_2$ huhesabiwa kwa kutumia fomula ya kinematiki.

$$v_2^2 = u_2^2 + 2a_2s_2$$ $$(0 \text{ m/s})^2 = (27.044 \text{ m/s})^2 + 2a_2(500 \text{ m})$$ $$0 = 731.4 + 1000a_2$$ $$a_2 = -\frac{731.4}{1000}$$ $$a_2 = -0.7314 \text{ m/s}^2$$

Muda $t_2$ wa awamu hii huhesabiwa kwa kutumia fomula ya kinematiki.

$$v_2 = u_2 + a_2t_2$$ $$0 \text{ m/s} = 27.044 \text{ m/s} + (-0.7314 \text{ m/s}^2)t_2$$ $$t_2 = \frac{27.044 \text{ m/s}}{0.7314 \text{ m/s}^2}$$ $$t_2 \approx 36.98 \text{ s}$$

Muda wote wa safari $T$ ni jumla ya muda wa kuongeza kasi na kupunguza kasi.

$$T = t_1 + t_2$$ $$T = 88.74 \text{ s} + 36.98 \text{ s}$$ $$T = 125.72 \text{ s}$$

Kikomo cha muda ni dakika 5, ambayo ni $5 \times 60 = 300 \text{ s}$.
Kwa kuwa muda wote wa safari ($125.72 \text{ s}$) ni mfupi kuliko kikomo cha muda ($300 \text{ s}$), mhandisi anaweza kufika kwa wakati.

Taarifa muhimu kwa meneja wa mradi:
Muda wote unaohitajika kwa safari ni takriban 125.72 sekunde.
Kikomo cha muda kilichowekwa ni 300 sekunde.

$$\boxed{\text{Mhandisi anaweza kufika kwa wakati. Muda wote wa safari ni takriban } \textbf{125.72 s}.}$$