Another method please

Step 1: Use the equation relating final velocity, initial velocity, acceleration, and displacement.

$v^{2} = u^{2} + 2as$

Step 2: Find displacement $s$ using $s = \frac{1}{2}at^{2}$.

Given $u = 0$ m/s, $a = 2$ m/s², $t = 10$ s.

$s = \frac{1}{2} \times 2 \times (10)^{2}$

$s = 1 \times 100 = 100$

m.

Step 3: Substitute into the velocity equation.

$v^{2} = (0)^{2} + 2 \times 2 \times 100$

$v^{2} = 0 + 400 = 400$

(m/s)².

Step 4: Solve for $v$.

$v = \sqrt{400} = 20$

m/s (taking positive root as speed increases from rest).

Final answer: $20$ m/s

20 m/s