Don't you have another method

March 18, 2026Physics

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Answer

20\ \mathrm{m/s}

5 steps

Find displacement $s$ using the formula for constant acceleration from rest.
$s = \frac{1}{2} a t^{2}$
Substitute $a = 2\ \mathrm{m/s^{2}}$ and $t = 10\ \mathrm{s}$ .
$s = \frac{1}{2} (2\ \mathrm{m/s^{2}}) (10\ \mathrm{s})^{2}$ $s = (1\ \mathrm{m/s^{2}}) (100\ \mathrm{s^{2}})$ $s = 100\ \mathrm{m}$
Use the formula relating final velocity, initial velocity, acceleration, and displacement.
$v^{2} = u^{2} + 2 a s$
Substitute $u = 0\ \mathrm{m/s}$ , $a = 2\ \mathrm{m/s^{2}}$ , and $s = 100\ \mathrm{m}$ .
$v^{2} = (0\ \mathrm{m/s})^{2} + 2 (2\ \mathrm{m/s^{2}}) (100\ \mathrm{m})$ $v^{2} = 0 + 400\ \mathrm{m^{2}/s^{2}}$ $v^{2} = 400\ \mathrm{m^{2}/s^{2}}$
Solve for $v$ .
$v = \sqrt{400\ \mathrm{m^{2}/s^{2}}}$ $v = 20\ \mathrm{m/s}$
Final velocity: $\boxed{20\ \mathrm{m/s}}$

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