Answer this physics question

The wire is suspended, meaning the upward magnetic force ($F_B$) must balance the downward gravitational force ($F_g$).
Given:
Length of wire, $L = 15 \text{ m}$
Mass of wire, $m = 50 \text{ g} = 0.050 \text{ kg}$ (converted to kilograms)
Magnetic field strength, $B = 0.50 \text{ T}$
Angle between wire and magnetic field, $\theta = 90^\circ$ (since it's at a right angle)
Acceleration due to gravity, $g = 9.8 \text{ m/s}^2$

The magnetic force on a current-carrying wire is given by:

The gravitational force (weight) of the wire is given by:

For the wire to be suspended, $F_B = F_g$:

Rearrange the formula to solve for $I$:

Since $\theta = 90^\circ$, $\sin\theta = \sin(90^\circ) = 1$.

Rounding to two significant figures, based on the given values (0.50 T, 50 g):