A body accelerates uniformly from rest at 2 ms-².calculate the magnitude of it's velocity after travelling 9m

Given:
Initial velocity, $u=0~\mathrm{m/s}$ (starts from rest).
Acceleration, $a=2~m/s^2$.
Distance travelled, $s=9~\mathrm{m}$.

Use the kinematic equation:
$v^2 = u^2 + 2as$

Step 1: Substitute the known values.
$v^2 = (0~m/s)^2 + 2(2~m/s^2)(9~m)$

Step 2: Simplify inside the parentheses first.
$v^2 = 0 + 2 \times 2~m/s^2 \times 9~\mathrm{m}$
$v^2 = 36~\mathrm{m^2/s^2}$

Step 3: Solve for $v$ (take the positive root for magnitude).
$v = \sqrt{36~m^2/s^2}$
$v = 6~\mathrm{m/s}$

6 m/s