A body accelerates uniformly from rest at 2 ms-².calculate the magnitude of it's velocity after travelling 9m

Given: Initial velocity, u=0~m/s (starts from rest). Acceleration, a=2~m/s². Distance travelled, s=9~m. Use the kinematic equation: v² = u² + 2as Step 1: Substitute the known values. v² = (0~m/s)² + 2(2~m/s²)(9~m) Step 2: Simplify inside the parentheses first. v² = 0 + 2 × 2~m/s² × 9~m; v² = 36~m²/s² Step 3: Solve for v (take the positive root for magnitude). v = √36~m²/s²; v = 6~m/s 6 m/s

A body accelerates uniformly from rest at 2 ms-².calculate the magnitude of it's velocity after travelling 9m

Given: Initial velocity, u=0~m/s (starts from rest). Acceleration, a=2~m/s². Distance travelled, s=9~m. Use the kinematic equation: v² = u² + 2as Step 1: Substitute the known values. v² = (0~m/s)² + 2(2~m/s²)(9~m) Step 2: Simplify inside the parentheses first. v² = 0 + 2 × 2~m/s² × 9~m; v² = 36~m²/s² Step 3: Solve for v (take the positive root for magnitude). v = √36~m²/s²; v = 6~m/s 6 m/s

Solved: A body accelerates uniformly from rest at 2…

Given:
Initial velocity, $u=0~\mathrm{m/s}$ (starts from rest).
Acceleration, $a=2~\mathrm{m/s}^2$ .
Distance travelled, $s=9~\mathrm{m}$ .

Use the kinematic equation:

v^2 = u^2 + 2as

Substitute the known values.
$v^2 = (0~\mathrm{m/s})^2 + 2(2~\mathrm{m/s}^2)(9~\mathrm{m})$
Simplify inside the parentheses first.
$v^2 = 0 + 2 \times 2~\mathrm{m/s}^2 \times 9~\mathrm{m}$ $v^2 = 36~\mathrm{m^2/s^2}$
Solve for $v$ (take the positive root for magnitude).
$v = \sqrt{36~\mathrm{m^2/s^2}}$ $v = 6~\mathrm{m/s}$
6 m/s

A body accelerates uniformly from rest at 2 ms-².calculate the magnitude of it's velocity after travelling 9m

Answer

Step-by-step solution

Substitute the known values.

Simplify inside the parentheses first.

Solve for $v$ (take the positive root for magnitude).

Try one yourself

Still stuck on this one?

More Physics Questions

A body accelerates uniformly from rest at 2 ms-².calculate the magnitude of it's velocity after travelling 9m

Answer

Step-by-step solution

Substitute the known values.

Simplify inside the parentheses first.

Solve for vvv (take the positive root for magnitude).

Try one yourself

Still stuck on this one?

More Physics Questions

Solve for $v$ (take the positive root for magnitude).