We read your photo as:

c. Write down the relationship between refracting angle A of a triangle and minimum deviation Dm and refractive index. d. Show that the pressure on a single molecule of a gas inside a box is given by p = (1/3)ρc2 where ρ = density, c = speed

Physics

ScanSolve AI Answer

Step-by-step solution

5 steps

My apologies, the previous answer was cut off. Let's finish 12. f. ii.

12. f. ii. Two-thirds of a radioactive nucleus remained after 32 days of decays. Calculate the half-life.
Let N0N_0 be the initial number of nuclei and NN be the number of nuclei remaining.
Given: N=23N0N = \frac{2}{3} N_0 and t=32t = 32 days.

  1. Use the radioactive decay formula.

    N=N0(12)t/T1/2N = N_0 \left(\frac{1}{2}\right)^{t/T_{1/2}}
  2. Substitute the given values.

    23N0=N0(12)32/T1/2\frac{2}{3} N_0 = N_0 \left(\frac{1}{2}\right)^{32/T_{1/2}}
  3. Divide both sides by N0N_0.

    23=(12)32/T1/2\frac{2}{3} = \left(\frac{1}{2}\right)^{32/T_{1/2}}
  4. Take the natural logarithm (or logarithm to any base) of both sides.

    ln⁡(23)=ln⁡((12)32/T1/2)\ln\left(\frac{2}{3}\right) = \ln\left(\left(\frac{1}{2}\right)^{32/T_{1/2}}\right) ln⁡(2)−ln⁡(3)=32T1/2(ln⁡(1)−ln⁡(2))\ln(2) - \ln(3) = \frac{32}{T_{1/2}} (\ln(1) - \ln(2)) ln⁡(2)−ln⁡(3)=−32T1/2ln⁡(2)\ln(2) - \ln(3) = -\frac{32}{T_{1/2}} \ln(2)
  5. Solve for T1/2T_{1/2}.

    T1/2=−32ln⁡(2)ln⁡(2)−ln⁡(3)T_{1/2} = -\frac{32 \ln(2)}{\ln(2) - \ln(3)} T1/2=−32×0.69310.6931−1.0986T_{1/2} = -\frac{32 \times 0.6931}{0.6931 - 1.0986} T1/2=−22.1792−0.4055T_{1/2} = -\frac{22.1792}{-0.4055} T1/2≈54.695 daysT_{1/2} \approx 54.695 \text{ days}

    The half-life is 54.7 days\boxed{\text{54.7 days}} (to 3 significant figures).

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp