This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Step 1: Calculate the combined resistance of the 2\, and 3\, resistors. These two resistors are connected in parallel. R_p = (R_1 × R_2)/(R_1 + R_2) R_p = (2\, × 3\,)/(2\, + 3\,) R_p = (6\,^2)/(5\,) R_p = 1.2\, The combined resistance of the 2\, and 3\, resistors is 1.2\,. Step 2: Calculate the total resistance in the circuit when the switch is closed. The equivalent resistance of the parallel combination (R_p = 1.2\,) is in series with the 6\, resistor. R_total = R_p + R_series R_total = 1.2\, + 6\, R_total = 7.2\, The total resistance in the circuit when the switch is closed is 7.2\,. Step 3: Calculate the potential difference across the 2\, resistor. First, calculate the total current (I_total) flowing from the 12\,V source using Ohm's Law. I_total = V_sourceR_total I_total = (12\,V)/(7.2\,) I_total = (120)/(72)\,A I_total = (5)/(3)\,A The potential difference across the parallel combination (V_p) is the product of the total current and the equivalent parallel resistance. The 2\, resistor is part of this parallel combination, so the potential difference across it is V_p. V_p = I_total × R_p V_p = (5)/(3)\,A × 1.2\, V_p = (5)/(3)\,A × (6)/(5)\, V_p = 2\,V The potential difference across the 2\, resistor is 2\,V. Send me the next one 📸