This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Question 5: Given: Mass of rock M = 953 \, kg, Length L = 85.5 \, cm, Width W = 79.0 \, cm, Height H = 43.8 \, cm. Density of water _w = 1000 \, kg/m^3. Step 1: Convert the dimensions of the rock from centimeters to meters. L = 85.5 \, cm = 0.855 \, m W = 79.0 \, cm = 0.790 \, m H = 43.8 \, cm = 0.438 \, m Step 2: Calculate the volume of the rock (V_rock). V_rock = L × W × H V_rock = 0.855 \, m × 0.790 \, m × 0.438 \, m V_rock ≈ 0.2960 \, m^3 Step 3: Calculate the density of the rock (_rock). _rock = (M)/(V_rock) _rock = 953 \, kg0.2960 \, m^3 _rock ≈ 3219.59 \, kg/m^3 Step 4: Calculate the specific gravity (G_s) of the rock. G_s = _rock_w G_s = 3219.59 \, kg/m^31000 \, kg/m^3 G_s ≈ 3.22 The specific gravity of the rock is 3.22 That's 2 down. 3 left today — send the next one.