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Calculate the density of a block of mass 20g and volume 10cm Give your answer in S.I unit.

Physics

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Answer

2000 kg/m3\text{2000 kg/m}^3

Step-by-step solution

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Haya, twende na swali la 16.

Swali la 16:
Hesabu density ya block yenye masi ya 20g20\text{g} na ujazo wa 10cm310\text{cm}^3. Toa jibu lako katika kitengo cha S.I.

  1. Andika formula ya density.

    Density (ρ\rho) inapatikana kwa kugawanya masi (mm) kwa ujazo (VV).

    ρ=mV\rho = \frac{m}{V}
  2. Badilisha vitengo vya masi na ujazo kuwa vitengo vya S.I.

    Kitengo cha S.I. cha masi ni kilogramu (kg).
    Kitengo cha S.I. cha ujazo ni mita za ujazo (m3\text{m}^3).

    Masi (mm) = 20 g20\text{ g}
    Kubadilisha gramu kuwa kilogramu: 1 kg=1000 g1\text{ kg} = 1000\text{ g}

    m=20 g×1 kg1000 g=0.02 kgm = 20\text{ g} \times \frac{1\text{ kg}}{1000\text{ g}} = 0.02\text{ kg}

    Ujazo (VV) = 10 cm310\text{ cm}^3
    Kubadilisha sentimita za ujazo kuwa mita za ujazo: 1 m=100 cm1\text{ m} = 100\text{ cm}, hivyo 1 m3=(100 cm)3=1,000,000 cm31\text{ m}^3 = (100\text{ cm})^3 = 1,000,000\text{ cm}^3.

    V=10 cm3×1 m31,000,000 cm3=0.00001 m3V = 10\text{ cm}^3 \times \frac{1\text{ m}^3}{1,000,000\text{ cm}^3} = 0.00001\text{ m}^3
  3. Fanya hesabu ya density kwa kutumia vitengo vya S.I.

    Sasa tumia masi na ujazo katika vitengo vya S.I.

    ρ=0.02 kg0.00001 m3\rho = \frac{0.02\text{ kg}}{0.00001\text{ m}^3} ρ=2000 kg/m3\rho = 2000\text{ kg/m}^3

    Density ya block ni:

    2000 kg/m3\text{2000 kg/m}^3
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