This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

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4800 liters
Fresh day SIR., let's solve.
1 a) Pressure is defined as the force applied perpendicular to the surface of an object per unit area over which that force is distributed. where is pressure, is force, and is area.
1 b) Four practical applications of pressure in the plumbing industry are:
2 a) Step 1: Calculate the total volume of the tank. The cross-sectional area is . The height is . Total volume of tank = Area Height Step 2: Calculate the volume of water in the tank. The tank is full of water. Step 3: Convert the volume of water to liters. Since :
2 b) Step 1: Calculate the height of the water. The tank is high and full. Step 2: Calculate the gauge pressure at the base of the tank. The formula for gauge pressure is , where is the density of water (), is the acceleration due to gravity (), and is the height of the water. Step 3: Calculate the total pressure at the base of the tank. Total pressure is the sum of atmospheric pressure () and gauge pressure.
3) An air lock is a bubble of air trapped in a pipe or plumbing system that obstructs or completely stops the flow of liquid. It is important in plumbing because air locks can prevent water from reaching fixtures, reduce the efficiency of heating systems, cause noisy pipes, and potentially damage pumps if they run dry.
4) A likely cause of leakage in plastic cisterns is material degradation due to prolonged exposure to ultraviolet (UV) radiation from sunlight or chemical attack from certain cleaning agents or water additives, which can make the plastic brittle and prone to cracking.
5 b) Required ways of controlling leakage in plastic cisterns include:
6 a) Intensity of pressure is another term for pressure, which is the force exerted per unit area. In fluid mechanics, it specifically refers to the pressure at a certain point within a fluid.
6 b) Step 1: Convert the dimensions of the cistern to meters. The cistern dimensions are . Assuming the height of the water is the smallest dimension, . Step 2: Calculate the intensity of pressure (gauge pressure) at the base of the cistern. Using the formula , where (density of water) and .
7)
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Fresh day SIR., let's solve. 1 a) Pressure is defined as the force applied perpendicular to the surface of an object per unit area over which that force is distributed.
This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.