Find the deceleration and Velocity of T³-2T+T

The position function $s(T)$ is given by:

$$s(T) = T^3 - 2T + T$$ $$s(T) = T^3 - T$$

Velocity $v(T)$ is the first derivative of $s(T)$:

$$v(T) = \frac{ds}{dT} = \frac{d}{dT}(T^3 - T)$$ $$v(T) = 3T^2 - 1$$

The velocity is $\boxed{3T^2 - 1}$.

Acceleration $a(T)$ is the first derivative of $v(T)$:

$$a(T) = \frac{dv}{dT} = \frac{d}{dT}(3T^2 - 1)$$ $$a(T) = 6T$$

Deceleration is the negative of acceleration.

$$\text{Deceleration} = -a(T)$$ $$\text{Deceleration} = -6T$$

The deceleration is $\boxed{-6T}$.