Identify the form of energy.

Here's the solution to the physics problem: a) State and calculate the form of mechanical energy stored in the jackfruit before being plucked by Juma from the tree. Step 1: Identify the form of energy. Before being plucked, the jackfruit is at a certain height above the ground, so it possesses gravitational potential energy. Step 2: Convert the mass to kilograms and state the given values. The mass of the jackfruit is 2500 g, which is 2.5 kg. The height is h = 4 m. The acceleration due to gravity is assumed to be g = 9.8 m/s^2. Step 3: Calculate the gravitational potential energy. The formula for gravitational potential energy is PE = mgh. PE = (2.5 kg)(9.8 m/s^2)(4 m) PE = 98 J The form of mechanical energy stored is gravitational potential energy, and its value is 98 J. b) Determine the kinetic energy of the fruit as it hits the ground stating, clearly the assumption and hence calculate the velocity with which it hits the ground. Step 1: State the assumption. The assumption is that mechanical energy is conserved during the fall, meaning air resistance is negligible. Therefore, all the initial gravitational potential energy is converted into kinetic energy just before impact. Step 2: Determine the kinetic energy as it hits the ground. According to the conservation of mechanical energy: KE_ground = PE_initial KE_ground = 98 J The kinetic energy of the fruit as it hits the ground is 98 J. Step 3: Calculate the velocity with which it hits the ground. The formula for kinetic energy is KE = (1)/(2)mv^2. 98 J = (1)/(2)(2.5 kg)v^2 196 = 2.5v^2 v^2 = (196)/(2.5) v^2 = 78.4 v = sqrt(78.4) v ≈ 8.85 m/s The velocity with which it hits the ground is approximately 8.85 m/s. c) Explain why the jackfruit comes to rest after hitting the ground and does not bounce back to the original height hence state the law shown by the behavior of the fruit. When the jackfruit hits the ground, its kinetic energy is converted into other forms of energy, primarily heat energy (due to friction and deformation), sound energy, and energy causing deformation of the fruit and the ground. This energy is dissipated into the surroundings and is not available to convert back into potential energy to make the fruit bounce to its original height. The behavior of the fruit demonstrates the Law of Conservation of Energy, which states that energy cannot be created or destroyed, but can be transformed from one form to another. In this case, mechanical energy is not conserved due to these energy transformations into non-mechanical forms. d) State clearly all energy changes that occur as the jackfruit falls from top to the ground. As the jackfruit falls from the top to the ground, the following energy changes occur: • Initially, the jackfruit possesses gravitational potential energy. • As it falls, its height decreases, and its speed increases. This means its gravitational potential energy is converted into kinetic energy. • Just before hitting the ground, most of its initial potential energy has been converted into kinetic energy. • Upon impact with the ground, this kinetic energy is then converted into heat energy, sound energy, and energy causing deformation of the jackfruit and the ground. What's next?