Demonstrate Boyle's Law using the provided pressure and volume data for a gas.

Boyle's Law states that for a fixed amount of gas at constant temperature, the pressure ($P$) and volume ($V$) are inversely proportional. This means their product, $P \times V$, remains constant.

We will calculate $P \times V$ for each pair of given values:

• For $P = 0.2500 \text{ Torr}$, $V = 2.8010 \text{ L}$: $P \times V = 0.2500 \text{ Torr} \times 2.8010 \text{ L} = 0.70025 \text{ Torr} \cdot \text{L}$
• For $P = 0.5000 \text{ Torr}$, $V = 1.4000 \text{ L}$: $P \times V = 0.5000 \text{ Torr} \times 1.4000 \text{ L} = 0.70000 \text{ Torr} \cdot \text{L}$
• For $P = 0.7500 \text{ Torr}$, $V = 0.9333 \text{ L}$: $P \times V = 0.7500 \text{ Torr} \times 0.9333 \text{ L} = 0.699975 \text{ Torr} \cdot \text{L}$
• For $P = 1.0000 \text{ Torr}$, $V = 0.6998 \text{ L}$: $P \times V = 1.0000 \text{ Torr} \times 0.6998 \text{ L} = 0.69980 \text{ Torr} \cdot \text{L}$
• For $P = 2.0000 \text{ Torr}$, $V = 0.3495 \text{ L}$: $P \times V = 2.0000 \text{ Torr} \times 0.3495 \text{ L} = 0.69900 \text{ Torr} \cdot \text{L}$
• For $P = 3.0000 \text{ Torr}$, $V = 0.2328 \text{ L}$: $P \times V = 3.0000 \text{ Torr} \times 0.2328 \text{ L} = 0.69840 \text{ Torr} \cdot \text{L}$
• For $P = 4.0000 \text{ Torr}$, $V = 0.1744 \text{ L}$: $P \times V = 4.0000 \text{ Torr} \times 0.1744 \text{ L} = 0.69760 \text{ Torr} \cdot \text{L}$
• For $P = 5.0000 \text{ Torr}$, $V = 0.1394 \text{ L}$: $P \times V = 5.0000 \text{ Torr} \times 0.1394 \text{ L} = 0.69700 \text{ Torr} \cdot \text{L}$

The calculated $P \times V$ values are consistently close to $0.700 \text{ Torr} \cdot \text{L}$, with minor variations due to experimental measurements. For example, the values range from $0.69700 \text{ Torr} \cdot \text{L}$ to $0.70025 \text{ Torr} \cdot \text{L}$. This demonstrates that as the pressure increases, the volume decreases proportionally, keeping their product approximately constant. Therefore, the provided data supports Boyle's Law.